Basic Calculator II
Implement a basic calculator to evaluate a simple expression string.
The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero.
You may assume that the given expression is always valid.
Some examples:
"3+2*2" = 7 " 3/2 " = 1 " 3+5 / 2 " = 5
Note: Do not use the eval built-in library function.
Credits:Special thanks to @ts for adding this problem and creating all test cases.
Solution
public class Solution {
public int calculate(String s) {
if (s == null || s.length() <= 0) return 0;
Stack<Integer> stack1 = new Stack<>();
Stack<Character> stack2 = new Stack<>();
for (int i = 0; i < s.length(); i++) {
char currentChar = s.charAt(i);
if (isOperand(currentChar)) {
if (currentChar == ')') {
while (stack2.peek() != '(') {
Character operand = stack2.pop();
stack1.push(operate(operand, stack1.pop(), stack1.pop()));
}
stack2.pop();
} else if (currentChar == '+' || currentChar == '-') {
while (!stack2.isEmpty()) {
if (stack2.peek() == '(') {
break;
}
stack1.push(operate(stack2.pop(), stack1.pop(), stack1.pop()));
}
stack2.push(currentChar);
} else {
stack2.push(currentChar);
}
} else if (Character.isDigit(currentChar)) {
int endIndex = i + 1;
while (endIndex < s.length() && Character.isDigit(s.charAt(endIndex))) {
endIndex++;
}
Integer currentInteger = Integer.valueOf(s.substring(i, endIndex));
if (!stack2.isEmpty() && (stack2.peek() == '*' || stack2.peek() == '/')) {
stack1.push(operate(stack2.pop(), stack1.pop(), currentInteger));
} else {
stack1.push(currentInteger);
}
i = endIndex - 1;
}
}
while (!stack2.isEmpty()) {
stack1.push(operate(stack2.pop(), stack1.pop(), stack1.pop()));
}
return stack1.pop();
}
private int operate(Character c, int a, int b) {
switch (c) {
case '+':
return a + b;
case '-':
return b - a;
case '*':
return a * b;
case '/':
return a / b;
}
return -1;
}
private boolean isOperand(char c) {
StringBuffer sb = new StringBuffer();
sb.append(c);
return "()+-/*".contains(sb.toString());
}
}